23x^2-170x+63=0

Solution for 23x^2-170x+63=0 equation:

23x^2-170x+63=0

a = 23; b = -170; c = +63;
Δ = b2-4ac
Δ = -1702-4·23·63
Δ = 23104
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{23104}=152$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-170)-152}{2*23}=\frac{18}{46}
=9/23
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-170)+152}{2*23}=\frac{322}{46}
=7
$